Short answer: you can use L'Hôpital's rule only when direct substitution gives the indeterminate form 0/0 or ∞/∞. Then lim f(x)/g(x) = lim f′(x)/g′(x), provided the new limit exists. You differentiate the top and bottom separately, not with the quotient rule.
Step 1: Always substitute first
Plug in the value. If you get a real number, that is the answer. If you get a nonzero number over 0, the limit is infinite or does not exist, and L'Hôpital does not apply.
Step 2: Check the form
- 0/0 or ∞/∞: apply the rule.
- 0·∞: rewrite as a fraction first, for example x·ln x = ln x / (1/x).
- ∞ − ∞: combine into one fraction first.
- 1∞, 00, ∞0: take ln, find that limit, then exponentiate.
Worked example: limx→0 sin x / x
Substitution gives 0/0. Differentiate top and bottom: cos x / 1 → cos 0 = 1.
Worked example: limx→∞ x² / ex
∞/∞ → 2x / ex (still ∞/∞) → 2 / ex → 0. You can apply the rule repeatedly as long as the form stays indeterminate.
Worked example: limx→0⁺ x·ln x
This is 0·(−∞). Rewrite as ln x / (1/x), which is −∞/∞. Differentiate: (1/x) / (−1/x²) = −x → 0.
Mistakes that cost marks
- Using the rule when the form is not 0/0 or ∞/∞. This gives wrong answers, not just lost method marks.
- Applying the quotient rule to f/g instead of differentiating f and g separately.
- Not showing the indeterminate form. Many mark schemes require you to state it before applying the rule.
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